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Question Number 46978 by rahul 19 last updated on 03/Nov/18

Answered by MrW3 last updated on 03/Nov/18

$$\frac{q}{p}=4-p\Rightarrow p=4-\frac{q}{p}$$$$\frac{r}{q}=4-q\Rightarrow q=4-\frac{r}{q}$$$$\frac{p}{r}=4-r\Rightarrow r=4-\frac{p}{r}$$$$\Rightarrow p+q+r=12-(\frac{q}{p}+\frac{r}{q}+\frac{p}{r})⩽12-3\times {}^3\sqrt{\frac{q}{p}\times \frac{r}{q}\times \frac{p}{r}}=12-3=9$$$$$$$$\Rightarrow answerC)iscorrect$$

Commented by rahul 19 last updated on 04/Nov/18

thanks sir ����

Answered by ajfour last updated on 03/Nov/18

$$p+q+r=4(p+q+r)-(p^2+q^2+r^2)$$$$\Rightarrow p^2+q^2+r^2=3(p+q+r)$$$$formaximump+q+r$$$$p=q=r=s\left(say\right);then$$$$3s^2=9s\Rightarrow s=0,3$$$${(p+q+r)}_{max}=3s=9.$$

Commented by rahul 19 last updated on 04/Nov/18

thanks sir ����

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