The velocity of a ship Q relqtive to a ship P is 10km/h in a direction N45^. E.If the velocity of P is 20km/h in a direction N60^. W.Find the actual velocity of Q in magnitude and direction.


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Question Number 47194 by Necxx last updated on 06/Nov/18

$T h e v e l o c i t y o f a s h i p Q r e l q t i v e t o$ $a s h i p P i s 10 k m / h i n a d i r e c t i o n$ $N 45^{.} E . I f t h e v e l o c i t y o f P i s 20 k m / h$ $i n a d i r e c t i o n N 60^{.} W . F i n d t h e$ $a c t u a l v e l o c i t y o f Q i n m a g n i t u d e$ $a n d d i r e c t i o n .$
Commented by Necxx last updated on 06/Nov/18

$p l e a s e h e l p$
Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

$p i c t u r e f o r c l a r i t y o f d i r e c t i o n . . .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

	${\vec{V}}_{p} = - 20 s i n 60^{o} i + 20 c o s 60^{o} j$ $v e l o c i t y o f Q r e l a t i v e t o P i s$ ${\vec{V}}_{Q} - {\vec{V}}_{P} = 10 s i n 45^{o} i + 10 c o s 45^{o} j$ ${\vec{V}}_{Q} = i (10 \times \frac{1}{\sqrt{2}} - 20 \times \frac{\sqrt{3}}{2}) + j (10 \times \frac{1}{\sqrt{2}} + 20 \times \frac{1}{2})$ ${\vec{V}}_{Q} = i (5 \times 1.41 - 10 \times 1.732) + j (5 \times 1.41 + 10)$ $= i (7.05 - 17.32) + j (7.05 + 10)$ $= i (- 10.27) + j (17.5)$ $p l s c h e c k . . .$
	Commented by Necxx last updated on 06/Nov/18

	$y e a h . . . . i c q l c u l a t e d t h e m o d u l u s$ $a n d d i r e c t i o n o f t h e v a l u e . i t s r e a l l y$ $c o r r e c t . T h a n k s$
	Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

	$t h a n k s . . .$
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