Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 47239 by JDlix last updated on 06/Nov/18

$$\frac{1.8\times {10}^6}{tan(89.9999°)}\sim \pi \left(upto9decimalplaces\right)$$$$canihavesomeexplanationshowitisworkedout?$$$$Thankyou!$$

Commented by MJS last updated on 07/Nov/18

$$\mathrm{I}\mathrm{guess}\mathrm{somebody}\mathrm{just}\mathrm{messed}\mathrm{around}\mathrm{a}\mathrm{bit}.$$$$\mathrm{you}\mathrm{can}\mathrm{find}\mathrm{many}\mathrm{almost}-\mathrm{identities}$$$$\pi \ln \left(\pi \right)=\frac{143851}{40000}(\mathrm{error}\approx -2.7\times {10}^{-10})$$$$\pi \ln \left(\pi \ln \left(\pi \right)\right)=\frac{100523}{25000}(\mathrm{error}\approx -2.6\times {10}^{-10})$$$$\pi =\frac{6955380174-\sqrt{3}}{2213966271}(\mathrm{error}\approx -5\times {10}^{-13})$$

Answered by MJS last updated on 07/Nov/18

$$\tan \left((90-\frac{1}{{10}^d})°\right)=\frac{1}{\tan \frac{\pi }{180\times {10}^d}}\approx \frac{180\times {10}^d}{\pi }\mathrm{with}d\in \mathbb{N}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com