Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 47243 by MrW3 last updated on 06/Nov/18

Answered by MJS last updated on 07/Nov/18

$$\mathrm{left}\mathrm{picture}$$$$\frac{8}{r}=\frac{H}{R}\Rightarrow r=\frac{8R}{H}$$$$v_{blue}=\frac{\pi R^2(H^2+8H+64)(H-8)}{3H^2}$$$$\mathrm{right}\mathrm{picture}$$$$\frac{H-2}{r}=\frac{H}{R}\Rightarrow r=R(1-\frac{2}{H})$$$$v_{blue}=\frac{\pi (H-2)r^2}{3}=\frac{\pi R^2{(H-2)}^3}{3H^2}$$$$$$$${(\mathrm{H}-2)}^3=(H^2+8H+64)(H-8)$$$$H=1+\sqrt{85}\approx 10.22\mathrm{cm}$$

Commented by MrW3 last updated on 07/Nov/18

$$thankyousir!$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com