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Question Number 47250 by Raj Singh last updated on 07/Nov/18

Answered by MJS last updated on 07/Nov/18

$$\mathrm{surface}\mathrm{of}\mathrm{cuboid}$$$$2\times (15\times 10+15\times 5+10\times 5)=550$$$$\mathrm{surface}\mathrm{of}\mathrm{cylinder}\left(\mathrm{without}\mathrm{bottom}\mathrm{\&}\mathrm{top}\right)$$$$2\times 3.5\pi \times 5=35\pi$$$$\mathrm{surface}\mathrm{of}\mathrm{bottom}\mathrm{\&}\mathrm{top}$$$$2\times {(3.5)}^2\pi =\frac{49}{2}\pi$$$$\mathrm{surface}\mathrm{of}\mathrm{remaining}\mathrm{body}$$$$550+35\pi -\frac{49}{2}\pi =550+\frac{21}{2}\pi \approx 582.{99\mathrm{cm}}^2$$

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