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Question Number 47508 by naka3546 last updated on 11/Nov/18

Commented by gunawan last updated on 11/Nov/18

$$xyz=1$$$$xy=\frac{1}{z}$$$$x+xy=5$$$$x(1+y)=5$$$$x=\frac{5}{1+y}$$$$y+\frac{1+y}{5}=29$$$$5y+1+y=29\times 5$$$$6y=145-1$$$$y=\frac{144}{6}=24$$$$so$$$$\frac{1}{x}=5$$$$\frac{1}{5}+\frac{1}{z}=5$$$$\frac{1}{z}=\frac{24}{5}$$$$z+\frac{1}{y}=\frac{5}{24}+\frac{1}{24}$$$$m=1n=4$$$$m+n=5$$$$$$

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