All Questions Topic List
Differentiation Questions
Previous in All Question Next in All Question
Previous in Differentiation Next in Differentiation
Question Number 47532 by 143jesus last updated on 11/Nov/18
4002+1002=
Answered by Joel578 last updated on 11/Nov/18
=160000+10000=170000=10017≈412.31
Answered by arcana last updated on 11/Nov/18
f(x+h)−f(x)h≈f′(x)f(x+h)−f(x)≈h⋅f′(x)f(x+h)≈f(x)+h⋅f′(x)f(x)=x,a=4002h=1002f′(x)=12xf(a+h)≈f(a)+h⋅f′(a)4002+1002=f(4002+1002)≈4002+1002(124002)≈400+100×100800=400+12.5=412.54002+1002≈412.5
Terms of Service
Privacy Policy
Contact: info@tinkutara.com