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Question Number 47552 by ggny last updated on 11/Nov/18

$$\frac{5(\mathrm{x}-2)}{4}=\frac{6\mathrm{x}-9}{5}\mathrm{plz}\mathrm{help}\mathrm{me}$$

Commented by maxmathsup by imad last updated on 11/Nov/18

$$weusetheequivalence\frac{a}{b}=\frac{c}{d}\iff \frac{a}{b}-\frac{c}{d}=0so$$$$\frac{5(x-2)}{4}=\frac{6x-9}{5}\iff \frac{5(x-2)}{4}-\frac{6x-9}{5}=0\iff \frac{25(x-2)-4(6x-9)}{20}=0\Rightarrow$$$$25x-50-24x+36=0\iff x-14=0\iff x=14$$

Answered by $@ty@m last updated on 11/Nov/18

Commented by $@ty@m last updated on 11/Nov/18

Answered by peter frank last updated on 11/Nov/18

$$\frac{5\mathrm{x}-10}{4}=\frac{6\mathrm{x}-9}{5}$$$$25\mathrm{x}-50=24\mathrm{x}-36$$$$\mathrm{x}=50-36$$$$\mathrm{x}=14$$

Answered by Rio Michael last updated on 11/Nov/18

$$\frac{5x-10}{4}=\frac{6x-9}{5}crossmultiply$$$$25x-50=24x-36liketermsononeside$$$$25x-24x=-36+50$$$$x=14$$$$$$

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