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Question Number 47566 by tanmay.chaudhury50@gmail.com last updated on 11/Nov/18
∫sin51x(sinx)49dx
Answered by Smail last updated on 12/Nov/18
A=∫sin(50x+x)sin49(x)dx=∫(sin(50x)cosx+cos(50x)sin(x))sin49(x)dx=∫(sin(50x)cos(x)sin49(x)+cos(50x)sin50(x))dx=∫(sin(50x)(150sin50x)′+(150sin(50x))′sin50(x))A=150sin(50x)sin50x
Answered by tanmay.chaudhury50@gmail.com last updated on 12/Nov/18
∫sin(50+1)x(sinx)49dx∫[sin50xcosx+cos50xsinx](sinx)49dx∫sin50xcosx(sinx)49+cos50x(sinx)50dx150∫sin50x×50cosx(sinx)49+50cos50x(sinx)50dx150∫[sin50x×ddx{(sinx)50}+(sinx)50×ddx(sin50x)]dx150∫ddx{sin50x×(sinx)50}dx150×{sin50x×(sinx)50}+c
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