A boy runs towards a man standing 150m away.Speed of boy is 5m/s and that of man is 10m/s.The time and distance of their meeting from the boy^. s position are a)15s b)5s and 150m c)10s and 50m d)10s and 100m


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Question Number 47814 by Necxx last updated on 15/Nov/18

$A b o y r u n s t o w a r d s a m a n s t a n d i n g$ $150 m a w a y . S p e e d o f b o y i s 5 m / s$ $a n d t h a t o f m a n i s 10 m / s . T h e$ $t i m e a n d d i s t a n c e o f t h e i r m e e t i n g$ $f r o m t h e {b o y}^{.} s p o s i t i o n a r e$ $a) 15 s b) 5 s a n d 150 m c) 10 s a n d 50 m$ $d) 10 s a n d 100 m$
Commented by Necxx last updated on 15/Nov/18

$p l e a s e h e l p$
	Answered by mr W last updated on 15/Nov/18

	$t = t i m e t h e y r u n$ $b o y r u n s d i s t a n c e 5 t$ $m a n r u n s d i s t a n c e 10 t$ $t h e y r u n t o g e t h e r 150 m e t e r s :$ $5 t + 10 t = 150$ $\Rightarrow t = 10 s$ $b o y r u n s 5 \times 10 = 50 m$ $\Rightarrow a n s w e r c)$
	Commented by Necxx last updated on 15/Nov/18

	$w o w . . . . . . T h a n k s . . . i t s c l e a r$
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