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Question Number 47947 by mr W last updated on 17/Nov/18

Commented by mr W last updated on 17/Nov/18

$$seeQ44017$$$$$$$$with\lambda =\frac{h}{R}=\tan \phi$$$$a=R\frac{\lambda }{\sin \theta +\lambda \cos \theta }$$$$b=R\sqrt{\frac{\lambda -\tan \theta }{\lambda +\tan \theta }}$$

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