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Question Number 48090 by peter frank last updated on 19/Nov/18

Answered by tanmay.chaudhury50@gmail.com last updated on 19/Nov/18

$$1)truevalueofproductoflength\times width$$$$=2.29\times 1.29=(2.30-0.01)(1.30-0.01)$$$$=2.30\times 1.30-0.01(2.30+1.30)+0.0001$$$$=2.30\times 1.30-3.60\times 0.01+0.0001$$$$productofestimatedvalue$$$$=2.30\times 1.30$$$$soabsoluteerror$$$$=2.30\times 1.30-3.60\times 0.01+0.0001-2.30\times 1.30$$$$=-0.0359$$$$relatveerror=\frac{-0.0359}{2.29\times 1.29}$$

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