Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 48204 by ajfour last updated on 20/Nov/18

2(x^4 −2x^2 +3)(y^4 −3y^2 +4)=7 Find (x,y) .

2(x4−2x2+3)(y4−3y2+4)=7Find(x,y).

Answered by ajfour last updated on 20/Nov/18

2[(x^2 −1)^2 +2][(y^2 −(3/2))^2 +(7/4)]= 7 ⇒ x = ±1, y = ±(√(3/2)) four points.

2[(x2−1)2+2][(y2−32)2+74]=7⇒x=±1,y=±32fourpoints.

Terms of Service

Privacy Policy

Contact: info@tinkutara.com