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Question Number 483 by 13/NaSaNa(N)056565 last updated on 25/Jan/15

∫(1/(√(x−1)))dx

1x1dx

Answered by 123456 last updated on 12/Jan/15

∫(dx/(√(x−1)))  u=x−1  du=dx  ∫(du/(√u))=∫u^(−1/2) du=(1/(1/2))u^(1/2) +c  =2(√u)+c=2(√(x−1))+c

dxx1u=x1du=dxduu=u1/2du=11/2u1/2+c=2u+c=2x1+c

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