Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 483 by 13/NaSaNa(N)056565 last updated on 25/Jan/15

∫(1/(√(x−1)))dx

$$\int\frac{\mathrm{1}}{\sqrt{{x}−\mathrm{1}}}{dx} \\ $$$$ \\ $$

Answered by 123456 last updated on 12/Jan/15

∫(dx/(√(x−1)))  u=x−1  du=dx  ∫(du/(√u))=∫u^(−1/2) du=(1/(1/2))u^(1/2) +c  =2(√u)+c=2(√(x−1))+c

$$\int\frac{{dx}}{\sqrt{{x}−\mathrm{1}}} \\ $$$${u}={x}−\mathrm{1} \\ $$$${du}={dx} \\ $$$$\int\frac{{du}}{\sqrt{{u}}}=\int{u}^{−\mathrm{1}/\mathrm{2}} {du}=\frac{\mathrm{1}}{\mathrm{1}/\mathrm{2}}{u}^{\mathrm{1}/\mathrm{2}} +{c} \\ $$$$=\mathrm{2}\sqrt{{u}}+{c}=\mathrm{2}\sqrt{{x}−\mathrm{1}}+{c} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com