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Question Number 48466 by Tawa1 last updated on 24/Nov/18

Answered by tanmay.chaudhury50@gmail.com last updated on 24/Nov/18

A(1,3) B(7,9) D(4,6) eqn AB (y−3)=((9−3)/(7−1))(x−1) y−3−x+1=0 y−x−2=0 point C(−2,0) eqn DE (y−6)=(−1)(x−4) y−6+x−4=0 y+x−10=0 point E(10,0) in triangle △CDE C(−2,0) D(4,6) E(10,0) area =(1/2)[x_1 (y_2 −y_3 )+x_2 (y_3 −y_1 )+x_3 (y_1 −y_2 )] =(1/2)[(−2)(6−0)+4(0−0)+10(0−6)] =(1/2)[−12−60]=−36 so area is 36 unit

A(1,3)B(7,9)D(4,6)eqnAB(y−3)=9−37−1(x−1)y−3−x+1=0y−x−2=0pointC(−2,0)eqnDE(y−6)=(−1)(x−4)y−6+x−4=0y+x−10=0pointE(10,0)intriangle△CDEC(−2,0)D(4,6)E(10,0)area=12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=12[(−2)(6−0)+4(0−0)+10(0−6)]=12[−12−60]=−36soareais36unit

Commented by $@ty@m last updated on 24/Nov/18

Alternative; In △CDE C(−2,0) D(4,6) E(10,0) ∴CD=(√(6^2 +6^2 ))=6(√2) DE=(√(6^2 +6^2 ))=6(√2) ∴ ar(△CDE )=(1/2)×6(√2)×6(√2) =36 sq. unit

Alternative;In△CDEC(−2,0)D(4,6)E(10,0)∴CD=62+62=62DE=62+62=62∴ar(△CDE)=12×62×62=36sq.unit

Commented by Tawa1 last updated on 24/Nov/18

God bless you sir

Godblessyousir

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