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Question Number 48528 by Pk1167156@gmail.com last updated on 25/Nov/18

The value of (√3) cot 20°− 4 cos 20°  is

Thevalueof3cot20°4cos20°is

Answered by math1967 last updated on 25/Nov/18

 (((√3)cos20−4cos20sin20)/(sin20))     =((tan60cos20−2sin40)/(sin20))  =((((sin60cos20)/(cos60))−2sin40)/(sin20))  =((2sin60cos 20−2sin40)/(sin20))  [(1/(cos60))=2]  =((sin(60+20)+sin (60−20)−2sin 40)/(sin 20))  =((sin80−sin40)/(sin20))=((2sin20cos60)/(sin 20))=1Ans

3cos204cos20sin20sin20=tan60cos202sin40sin20=sin60cos20cos602sin40sin20=2sin60cos202sin40sin20[1cos60=2]=sin(60+20)+sin(6020)2sin40sin20=sin80sin40sin20=2sin20cos60sin20=1Ans

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