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Question Number 48528 by Pk1167156@gmail.com last updated on 25/Nov/18
Thevalueof3cot20°−4cos20°is
Answered by math1967 last updated on 25/Nov/18
3cos20−4cos20sin20sin20=tan60cos20−2sin40sin20=sin60cos20cos60−2sin40sin20=2sin60cos20−2sin40sin20[1cos60=2]=sin(60+20)+sin(60−20)−2sin40sin20=sin80−sin40sin20=2sin20cos60sin20=1Ans
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