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Question Number 48977 by ggny last updated on 30/Nov/18

Answered by $@ty@m last updated on 01/Dec/18

x+4=10(2x−3) x+4=20x−30 19x=34 x=((34)/(19))=1((15)/(19))

$${x}+\mathrm{4}=\mathrm{10}\left(\mathrm{2}{x}−\mathrm{3}\right) \\ $$$${x}+\mathrm{4}=\mathrm{20}{x}−\mathrm{30} \\ $$$$\mathrm{19}{x}=\mathrm{34} \\ $$$${x}=\frac{\mathrm{34}}{\mathrm{19}}=\mathrm{1}\frac{\mathrm{15}}{\mathrm{19}} \\ $$

Answered by hknkrc46 last updated on 01/Dec/18

0,55(x+4)=5,5(2x−3) ((0,55)/(5,5))=((2x−3)/(x+4)) ⇒ ((100.0,55)/(100.5,5))=((2x−3)/(x+4)) ⇒ ((55)/(550))=((2x−3)/(x+4)) { ((55)/(550))=((55/55)/(550/55))=(1/(10)) } (1/(10))=((2x−3)/(x+4)) ⇒ 1.(x+4)=10.(2x−3) ⇒ x+4=20x−30 ⇒ +4+30=20x−x ⇒ 34=19x ⇒ ((34)/(19))=((19x)/(19)) ⇒ ((34)/(19))=x

$$\mathrm{0},\mathrm{55}\left({x}+\mathrm{4}\right)=\mathrm{5},\mathrm{5}\left(\mathrm{2}{x}−\mathrm{3}\right) \\ $$$$\frac{\mathrm{0},\mathrm{55}}{\mathrm{5},\mathrm{5}}=\frac{\mathrm{2}{x}−\mathrm{3}}{{x}+\mathrm{4}}\:\Rightarrow\:\frac{\mathrm{100}.\mathrm{0},\mathrm{55}}{\mathrm{100}.\mathrm{5},\mathrm{5}}=\frac{\mathrm{2}{x}−\mathrm{3}}{{x}+\mathrm{4}}\:\Rightarrow\:\frac{\mathrm{55}}{\mathrm{550}}=\frac{\mathrm{2}{x}−\mathrm{3}}{{x}+\mathrm{4}} \\ $$$$\left\{\:\frac{\mathrm{55}}{\mathrm{550}}=\frac{\mathrm{55}/\mathrm{55}}{\mathrm{550}/\mathrm{55}}=\frac{\mathrm{1}}{\mathrm{10}}\:\right\} \\ $$$$\frac{\mathrm{1}}{\mathrm{10}}=\frac{\mathrm{2}{x}−\mathrm{3}}{{x}+\mathrm{4}}\:\Rightarrow\:\mathrm{1}.\left({x}+\mathrm{4}\right)=\mathrm{10}.\left(\mathrm{2}{x}−\mathrm{3}\right) \\ $$$$\Rightarrow\:{x}+\mathrm{4}=\mathrm{20}{x}−\mathrm{30}\:\Rightarrow\:+\mathrm{4}+\mathrm{30}=\mathrm{20}{x}−{x} \\ $$$$\Rightarrow\:\mathrm{34}=\mathrm{19}{x}\:\Rightarrow\:\frac{\mathrm{34}}{\mathrm{19}}=\frac{\mathrm{19}{x}}{\mathrm{19}}\:\Rightarrow\:\frac{\mathrm{34}}{\mathrm{19}}={x} \\ $$$$ \\ $$

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