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Question Number 48993 by Raj Singh last updated on 01/Dec/18
Answered by $@ty@m last updated on 01/Dec/18
Inordertosavetime,I′llwriteainsteadofa→LHS=[a×bb×cc×a]=(a×b).{(b×c)×(c×a)}=(a×b).{d×(c×a)}whered=b×c=(a×b).{(d.a)c−(d.c)a}=(a×b).{[bca]c−[bcc]a}=(a×b).{[bca]c−0}∵[bcc]=0=[bca](a×b.c)=[bca][abc]=[abc][abc]=[abc]2=RHS
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