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Question Number 49121 by Pk1167156@gmail.com last updated on 03/Dec/18

Answered by mr W last updated on 03/Dec/18

1−((8/h))^3 =(((h−2)/h))^3 1−64((2/h))^3 =(1−(2/h))^3 1−64((2/h))^3 =1−3((2/h))+3((2/h))^2 −((2/h))^3 −3((2/h))+3((2/h))^2 +63((2/h))^3 =0 −3+3((2/h))+63((2/h))^2 =0 ⇒(2/h)=((−3+(√(9+4×3×63)))/(2×63))=(((√(85))−1)/(42)) ⇒h=((84)/((√(85))−1))=(√(85))+1≈10.22 cm

1−(8h)3=(h−2h)31−64(2h)3=(1−2h)31−64(2h)3=1−3(2h)+3(2h)2−(2h)3−3(2h)+3(2h)2+63(2h)3=0−3+3(2h)+63(2h)2=0⇒2h=−3+9+4×3×632×63=85−142⇒h=8485−1=85+1≈10.22cm

Commented by Pk1167156@gmail.com last updated on 06/Dec/18

Thank you sir

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