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Question Number 49197 by Tawa1 last updated on 04/Dec/18

A bus travelling along a straight road at 100 km/hr and the bus conductor walks at 6 km/hr on the floor of the bus and in the same direction as the bus. Find the speed of the conductor relative to the road, and relative to the bus. If the bus conductor now walks at the same rate but in opposite direction as the bus, find his new speed relative to the road. Answers 106 km/hr , 64 km/hr , 94 km/hr

$$\mathrm{A}\:\mathrm{bus}\:\mathrm{travelling}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{at}\:\mathrm{100}\:\mathrm{km}/\mathrm{hr}\:\:\mathrm{and}\:\mathrm{the}\:\mathrm{bus}\: \\ $$$$\mathrm{conductor}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{6}\:\mathrm{km}/\mathrm{hr}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{conductor}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road},\:\mathrm{and}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{bus}.\:\:\mathrm{If}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{now}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{rate}\:\mathrm{but}\:\mathrm{in}\:\mathrm{opposite} \\ $$$$\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus},\:\:\mathrm{find}\:\mathrm{his}\:\mathrm{new}\:\mathrm{speed}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road}. \\ $$$$ \\ $$$$\mathrm{Answers} \\ $$$$\mathrm{106}\:\mathrm{km}/\mathrm{hr}\:,\:\:\:\:\:\:\mathrm{64}\:\mathrm{km}/\mathrm{hr}\:,\:\:\:\:\:\:\:\:\:\mathrm{94}\:\mathrm{km}/\mathrm{hr} \\ $$

Commented by afachri last updated on 04/Dec/18

v_(conductor ) relative to road = 100 − 6 = 94 km/h

$${v}_{\mathrm{conductor}\:} \mathrm{relative}\:\mathrm{to}\:\mathrm{road}\:=\:\mathrm{100}\:−\:\mathrm{6} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\mathrm{94}\:\mathrm{km}/\mathrm{h} \\ $$

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