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Question Number 49225 by AdqhK ÐQeQqQ last updated on 04/Dec/18
∫1z(z17+1)=??findplease
Answered by arvinddayama01@gmail.com. last updated on 04/Dec/18
∫1z(z17+1).z16z16dzz17=td.w.r.tozz16dz=117dt117∫dtt(t+1)117∫[1t−1t+1]dt117ln(tt+1)+C117ln(z17z17+1)+C∵∫1x(xn+1)dx=1nln(xnxn+1)+C
Commented by AdqhK ÐQeQqQ last updated on 04/Dec/18
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