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Question Number 49242 by maxmathsup by imad last updated on 04/Dec/18

let z from C and θ from R and z^2  +2zcosθ +1 =0 find the value of  z^(2n)  +2zcos(nθ)+1 .

$${let}\:{z}\:{from}\:{C}\:{and}\:\theta\:{from}\:{R}\:{and}\:{z}^{\mathrm{2}} \:+\mathrm{2}{zcos}\theta\:+\mathrm{1}\:=\mathrm{0}\:{find}\:{the}\:{value}\:{of} \\ $$$${z}^{\mathrm{2}{n}} \:+\mathrm{2}{zcos}\left({n}\theta\right)+\mathrm{1}\:. \\ $$$$ \\ $$

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