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Question Number 49296 by peter frank last updated on 05/Dec/18

Answered by kaivan.ahmadi last updated on 05/Dec/18

$$\frac{\mathrm{df}}{\mathrm{dx}}={2\mathrm{xysiny}}^2\mathrm{x}+{\mathrm{x}}^2{\mathrm{ycosy}}^2\mathrm{x}$$$$\mathrm{and}$$$$\frac{\mathrm{df}}{\mathrm{dy}}={\mathrm{x}}^2{\mathrm{siny}}^2\mathrm{x}+{\mathrm{x}}^2\mathrm{y}.{2\mathrm{ycosy}}^2\mathrm{x}=$$$${\mathrm{x}}^2{\mathrm{siny}}^2\mathrm{x}+{2\mathrm{x}}^2{\mathrm{y}}^2{\mathrm{cosy}}^2\mathrm{x}$$

Answered by kaivan.ahmadi last updated on 05/Dec/18

$$2.$$$$\frac{\mathrm{df}}{\mathrm{dx}}=\mathrm{ycosxy}$$$$\frac{\mathrm{df}}{\mathrm{dy}}=\mathrm{xcosxy}$$

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