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Question Number 49356 by peter frank last updated on 06/Dec/18

Commented by peter frank last updated on 07/Dec/18

$$\mathrm{am}\mathrm{getting}\mathrm{greatest}\mathrm{area}\mathrm{is}4\pi \mathrm{a}.$$

Answered by tanmay.chaudhury50@gmail.com last updated on 06/Dec/18

$$2)solvex+y-1=0$$$$y^2=6x$$$${(1-x)}^2=6x$$$$1-2x+x^2-6x=0$$$$x^2-8x+1=0$$$$x_1+x_2=-(-8)=8$$$$\frac{x_1+x_2}{2}=4$$$$y=1-x$$$$y_1=1-x_1$$$$y_2=1-x_2$$$$y_1+y_2=2-(x_1+x_2)=2-8=-6$$$$\frac{y_1+y_2}{2}=-3$$$$sothemidpointsofchords(4,-3)$$

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