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Question Number 49463 by Pk1167156@gmail.com last updated on 07/Dec/18
If7log7(x2−4x+5)=x−1,xmayhavevalues
Answered by tanmay.chaudhury50@gmail.com last updated on 07/Dec/18
ax=mx=logamlog7(x2−4x+5)=log7(x−1)x2−4x+5=x−1x2−5x+6=0(x−2)(x−3)=0x=2and3
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