show that the area of the triangle whose vertics area (0,0,0) , (x_1 ,y_1 ,z_1 ) , (x_2 ,y_(2,) z_2 ) is 1/2((√(Σ(y_1 z_2 −y_2 z


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Question Number 49466 by munnabhai455111@gmail.com last updated on 07/Dec/18

$s h o w t h a t t h e a r e a o f t h e t r i a n g l e w h o s e v e r t i c s a r e a (0, 0, 0), (x_{1}, y_{1}, z_{1}), (x_{2}, y_{2,} z_{2}) i s 1 / 2 (\sqrt{Σ {(y_{1} z_{2} - y_{2} z_{1})}^{2} .}$
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