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Question Number 49642 by maxmathsup by imad last updated on 08/Dec/18
ifa+b=sanda3+b3=tfinda2+b2anda4+b4intermsofsandt.
Answered by mr W last updated on 08/Dec/18
a3+b3=(a+b)(a2−ab+b2)=(a+b)[(a+b)2−3ab]t=s(s2−3ab)⇒ab=13(s2−ts)a2+b2=a2+2ab+b2−2ab=(a+b)2−2ab=s2−23(s2−ts)=13(s2+2ts)a4+b4=(a2+b2)2−2(ab)2=19(s2+2ts)2−29(s2−ts)2=19(s4+4t2s2+2st)−29(s4+t2s2−2st)=19(2t2s2+6st−s4)
Commented by maxmathsup by imad last updated on 08/Dec/18
thankyousir.
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