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Question Number 49691 by Rio Michael last updated on 09/Dec/18

$$simplify\frac{{log}_{3}64\times {log}_{4}243}{{log}_{2}16}$$

Answered by math1967 last updated on 09/Dec/18

$$\frac{{log}_3{4}^3\times {log}_4{3}^5}{{log}_2{2}^4}=\frac{3{log}_{3}4\times 5{log}_{4}3}{4{log}_{2}2}$$$$=\frac{3\times 5{log}_{3}4\times {log}_{4}3}{4\times 1}=\frac{15\times 1}{4}=3.75ans$$

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