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Question Number 49761 by rahul 19 last updated on 10/Dec/18
Calculate:∫sin2xcos2x(sin3x+cos3x)2dx
Answered by tanmay.chaudhury50@gmail.com last updated on 10/Dec/18
∫tan2xcos4xcos6x(1+tan3x)3dx∫tan2xsec2x(1+tan3x)3dx=13∫d(1+tan3x)(1+tan3x)3dx=13×(1+tan3x)−2−2=1−6×1(1+tan3x)2+c
Commented by rahul 19 last updated on 10/Dec/18
thank you sir!��
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