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Question Number 49976 by ajfour last updated on 12/Dec/18

Commented by ajfour last updated on 13/Dec/18

$$ThanksSir,i^{\prime }llbetterthisquestion.$$

Commented by ajfour last updated on 12/Dec/18

$$Findr.$$

Commented by mr W last updated on 12/Dec/18

$$\frac{R-r}{r}=\frac{r}{2R-r}$$$$2R^2-3Rr+r^2=r^2$$$$\Rightarrow r=\frac{2R}{3}$$

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