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Question Number 50279 by Saorey last updated on 15/Dec/18

 { ((x+y=6)),((y+z=10)) :}  (x,y,z>0)

$$\begin{cases}{\mathrm{x}+\mathrm{y}=\mathrm{6}}\\{\mathrm{y}+\mathrm{z}=\mathrm{10}}\end{cases}\:\:\left(\mathrm{x},\mathrm{y},\mathrm{z}>\mathrm{0}\right) \\ $$

Answered by mr W last updated on 15/Dec/18

if x,y,z are integers,then  (x,y,z)=(1,5,5)/(2,4,6)/(3,3,7)/(4,2,8)/(5,1,9)  if x,y,z are real, then  x=6−a  y=a  z=10−a  with 0<a<6

$${if}\:{x},{y},{z}\:{are}\:{integers},{then} \\ $$ $$\left({x},{y},{z}\right)=\left(\mathrm{1},\mathrm{5},\mathrm{5}\right)/\left(\mathrm{2},\mathrm{4},\mathrm{6}\right)/\left(\mathrm{3},\mathrm{3},\mathrm{7}\right)/\left(\mathrm{4},\mathrm{2},\mathrm{8}\right)/\left(\mathrm{5},\mathrm{1},\mathrm{9}\right) \\ $$ $${if}\:{x},{y},{z}\:{are}\:{real},\:{then} \\ $$ $${x}=\mathrm{6}−{a} \\ $$ $${y}={a} \\ $$ $${z}=\mathrm{10}−{a} \\ $$ $${with}\:\mathrm{0}<{a}<\mathrm{6} \\ $$

Answered by Rasheed.Sindhi last updated on 15/Dec/18

x+y=6 ∧ x,y>0⇒           0 <x,y<6⇒x,y∈(0,6)  y+z=10 ∧ y,z>0⇒            0<y,z<10⇒y,z∈(0,10)  x∈(0,6)   y∈ (0,6)∩(0,10)=(0,6)  z∈(4,10)

$$\mathrm{x}+\mathrm{y}=\mathrm{6}\:\wedge\:\mathrm{x},\mathrm{y}>\mathrm{0}\Rightarrow \\ $$ $$\:\:\:\:\:\:\:\:\:\mathrm{0}\:<\mathrm{x},\mathrm{y}<\mathrm{6}\Rightarrow\mathrm{x},\mathrm{y}\in\left(\mathrm{0},\mathrm{6}\right) \\ $$ $$\mathrm{y}+\mathrm{z}=\mathrm{10}\:\wedge\:\mathrm{y},\mathrm{z}>\mathrm{0}\Rightarrow \\ $$ $$\:\:\:\:\:\:\:\:\:\:\mathrm{0}<\mathrm{y},\mathrm{z}<\mathrm{10}\Rightarrow\mathrm{y},\mathrm{z}\in\left(\mathrm{0},\mathrm{10}\right) \\ $$ $$\mathrm{x}\in\left(\mathrm{0},\mathrm{6}\right)\: \\ $$ $$\mathrm{y}\in\:\left(\mathrm{0},\mathrm{6}\right)\cap\left(\mathrm{0},\mathrm{10}\right)=\left(\mathrm{0},\mathrm{6}\right) \\ $$ $$\mathrm{z}\in\left(\mathrm{4},\mathrm{10}\right) \\ $$ $$\:\: \\ $$

Commented byRasheed.Sindhi last updated on 16/Dec/18

THANKS for your warm welcome SIR!

$$\mathrm{THANKS}\:\mathrm{for}\:\mathrm{your}\:\mathrm{warm}\:\mathrm{welcome}\:{SIR}! \\ $$

Commented bymr W last updated on 15/Dec/18

nice to ♮seeε you again sir!  great come back!

$${nice}\:{to}\:\natural{see}\varepsilon\:{you}\:{again}\:{sir}! \\ $$ $${great}\:{come}\:{back}! \\ $$

Commented bymr W last updated on 16/Dec/18

thanks for coming back sir!

$${thanks}\:{for}\:{coming}\:{back}\:{sir}! \\ $$

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