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Question Number 50390 by Abdo msup. last updated on 16/Dec/18
$${study}\:{the}\:{sequence}\:{u}_{\mathrm{1}} ={ln}\left(\mathrm{2}\right)\:{and} \\ $$$${u}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}−\mathrm{1}} {ln}\left(\mathrm{2}−{u}_{{k}} \right)\:. \\ $$