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Question Number 50689 by Tawa1 last updated on 18/Dec/18
Ifcisthelinesegementfrom(0,0,0)to(1,2,3)find∫xeyzds
Answered by mr W last updated on 19/Dec/18
x−11=y−22=z−33⇒y=2x⇒z=3xds=(dx)2+(dy)2+(dz)2=1+22+32dx=14dx∫xeyzds=∫01xe6x214dx=1412∫01e6x2d(6x2)=1412[e6x2]01=1412(e6−1)
Commented by Tawa1 last updated on 19/Dec/18
Godblessyousir
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