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Question Number 50730 by ajfour last updated on 19/Dec/18

$$\sqrt{x-a}+\sqrt{x-b}+\sqrt{x-c}+x=d$$$$solveforx.$$

Answered by behi83417@gmail.com last updated on 21/Dec/18

$$aftersquaringandsymplifingigot$$$$thisequtition:$$$$9{\mathbf{x}}^4+{\mathbf{Ax}}^3+{\mathbf{Bx}}^2+\mathbf{Cx}+\mathbf{D}=0$$$$\mathbf{A}=-24(a+b)+12d-10$$$$\mathbf{B}=22{(a+b)}^2+8(1-2d)(a+b)-2d^2+10c+1$$$$\mathbf{C}=-16{(a+b)}^3-2(1-2d){(a+b)}^2-$$$$-8(c-4d^2)(a+b)-2c-4dc-2d^2-4d^3$$$$\mathbf{D}={(a+b)}^4+2(c-d^2){(a+b)}^2+{(c+d^2)}^2$$

Commented by ajfour last updated on 21/Dec/18

$$Sir,pleasecheckif$$$$a=31,b=47,c=55,d=65$$$$weshouldgetx=56.$$

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