x^2 −y^2 =a,a≠0 y^2 −z^2 =b,b≠0 z^2 −x^2 =c,c≠0 solve for :x,y,z.


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 50747 by behi83417@gmail.com last updated on 19/Dec/18

$x^{2} - y^{2} = a, a \neq 0$ $y^{2} - z^{2} = b, b \neq 0$ $z^{2} - x^{2} = c, c \neq 0$ $s o l v e f o r : x, y, z .$
Commented by behi83417@gmail.com last updated on 19/Dec/18

$y e s . s i r . f i x e d .$
Commented by ajfour last updated on 19/Dec/18

$a + b + c = 0 (o b v i o u s l y) .$
	Answered by mr W last updated on 20/Dec/18

	$x^{2} - y^{2} = a$ $x^{2} - y^{2} = - (b + c)$ $i f a \neq - (b + c) \Rightarrow n o s o l u t i o n$ $i f a = - (b + c) \Rightarrow i n f i n i t e s o l u t i o n s :$ $x = t$ $y = \pm \sqrt{t^{2} - a}$ $z = \pm \sqrt{t^{2} + c}$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum