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Question Number 50802 by Pk1167156@gmail.com last updated on 20/Dec/18

Commented by Pk1167156@gmail.com last updated on 20/Dec/18

help soon please!

Commented by Abdo msup. last updated on 20/Dec/18

4^(x^2 −x−6)  =7 ⇔(x^2 −x−6)ln(4)=ln(7) ⇔  x^2 −x−6 =((ln(7))/(ln)4))) ⇔x^2 −x−6 =log_4 (7) ⇒  x^2 −x−6−log_4 (7)=0  Δ =1−4(−6−log_4 (7))=25 +4log_4 (7)>0 ⇒  x_1 =((1+(√(25+4log_4 (7))))/2)  and  x_2 =((1−(√(25+4log_4 (7))))/2)

4x2x6=7(x2x6)ln(4)=ln(7)x2x6=ln(7)ln)4)x2x6=log4(7)x2x6log4(7)=0Δ=14(6log4(7))=25+4log4(7)>0x1=1+25+4log4(7)2andx2=125+4log4(7)2

Answered by hassentimol last updated on 20/Dec/18

Answers are :  S = {x  =  0.5  +_−    (((√(25+4×log_4 (7))) )/2)}

Answersare:S={x=0.5+25+4×log4(7)2}

Commented by Pk1167156@gmail.com last updated on 20/Dec/18

solution please!

Answered by afachri last updated on 20/Dec/18

                                 4^(x^2 −x−6)  = 7                              log _4 (7)      = x^2 −x−6   x^2 −x−(6+log _4 (7)) = 0  to find x_(1,2)  :  ((−b ± (√(b^2 −4ac )))/(2a))  x_(1,2 )  =  ((1 ± (√(1^  +  4(6+log_4 (7))^ )))/2)   x_(1,2 )  =  ((1 ± (√(25 + 4log _4 (7)^ )))/2)

4x2x6=7log4(7)=x2x6x2x(6+log4(7))=0tofindx1,2:b±b24ac2ax1,2=1±1+4(6+log4(7))2x1,2=1±25+4log4(7)2

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