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Question Number 50835 by Tawa1 last updated on 21/Dec/18

Commented by Tawa1 last updated on 21/Dec/18

Please help me solve it with diagram

$$\mathrm{Please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{solve}\:\mathrm{it}\:\mathrm{with}\:\mathrm{diagram} \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 21/Dec/18

1)i)acc=w^2 x=4π^2 n^2 x=4×π^2 ×50^2 ×2×10^(−2) =200π^2 =1973.92meter/sec^2 velocity v=w(√(a^2 −x^2 )) velocity at middle v=2πn(√(a^2 −x^2 )) v=2π×50×(√((4×10^(−2) )^2 −(2×10^(−2) )^2 )) =100π×10^(−2) (√(12)) =π(√(12)) metrt/sec ii)acc=4π^2 n^2 x =4π^2 ×50^2 ×4×10^(−2) =400π^2 =3947.84m/sec^2 velocity at 4cm=0 pls che4k...

$$\left.\mathrm{1}\left.\right){i}\right){acc}={w}^{\mathrm{2}} {x}=\mathrm{4}\pi^{\mathrm{2}} {n}^{\mathrm{2}} {x}=\mathrm{4}×\pi^{\mathrm{2}} ×\mathrm{50}^{\mathrm{2}} ×\mathrm{2}×\mathrm{10}^{−\mathrm{2}} \\ $$$$\:\:\:=\mathrm{200}\pi^{\mathrm{2}} =\mathrm{1973}.\mathrm{92}{meter}/{sec}^{\mathrm{2}} \\ $$$${velocity}\:{v}={w}\sqrt{{a}^{\mathrm{2}} −{x}^{\mathrm{2}} }\: \\ $$$${velocity}\:{at}\:{middle}\:{v}=\mathrm{2}\pi{n}\sqrt{{a}^{\mathrm{2}} −{x}^{\mathrm{2}} }\: \\ $$$${v}=\mathrm{2}\pi×\mathrm{50}×\sqrt{\left(\mathrm{4}×\mathrm{10}^{−\mathrm{2}} \right)^{\mathrm{2}} −\left(\mathrm{2}×\mathrm{10}^{−\mathrm{2}} \right)^{\mathrm{2}} }\: \\ $$$$=\mathrm{100}\pi×\mathrm{10}^{−\mathrm{2}} \sqrt{\mathrm{12}}\: \\ $$$$=\pi\sqrt{\mathrm{12}}\:{metrt}/{sec} \\ $$$$\left.{ii}\right){acc}=\mathrm{4}\pi^{\mathrm{2}} {n}^{\mathrm{2}} {x} \\ $$$$=\mathrm{4}\pi^{\mathrm{2}} ×\mathrm{50}^{\mathrm{2}} ×\mathrm{4}×\mathrm{10}^{−\mathrm{2}} =\mathrm{400}\pi^{\mathrm{2}} =\mathrm{3947}.\mathrm{84}{m}/{sec}^{\mathrm{2}} \\ $$$${velocity}\:{at}\:\mathrm{4}{cm}=\mathrm{0} \\ $$$${pls}\:{che}\mathrm{4}{k}... \\ $$$$ \\ $$$$ \\ $$

Commented by Tawa1 last updated on 21/Dec/18

God bless you sir. Any diagram to it sir and the second one

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{Any}\:\mathrm{diagram}\:\mathrm{to}\:\mathrm{it}\:\mathrm{sir}\:\mathrm{and}\:\mathrm{the}\:\mathrm{second}\:\mathrm{one} \\ $$

Commented by Tawa1 last updated on 21/Dec/18

God bless you sir. Any diagram sir with the second question

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{Any}\:\mathrm{diagram}\:\mathrm{sir}\:\mathrm{with}\:\mathrm{the}\:\mathrm{second}\:\mathrm{question} \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 21/Dec/18

is the answer correct for question no1... i am trying to solve 2nd questiin...

$${is}\:{the}\:{answer}\:{correct}\:{for}\:{question}\:{no}\mathrm{1}... \\ $$$${i}\:{am}\:{trying}\:{to}\:{solve}\:\mathrm{2}{nd}\:{questiin}... \\ $$

Commented by Tawa1 last updated on 21/Dec/18

i don′t know sir but i will use your workings

$$\mathrm{i}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{sir}\:\mathrm{but}\:\mathrm{i}\:\mathrm{will}\:\mathrm{use}\:\mathrm{your}\:\mathrm{workings} \\ $$

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