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Question Number 50932 by Tawa1 last updated on 22/Dec/18
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Dec/18
log(logac)2logba=−32[(logac)2]−32=logba(logac)−3=logbaletlogea=lna=plnb=qlnc=r(lnclna)−3=(lnalnb)(rp)−3=(pq)1(rp)3=pqpq×r3p3=1p2=r3q....(1)eqnlogcb−logac=2qr−rp=2pq−r2=2rp....(2)eqnwait...loga(b2018c2019)=xax=b2018c2019xlna=2018lnb+2019lncx=2018q+2019rpx=2000q+2000rp+18q+19rpx=1000(2q+2rp)+(18q+19rp)soremainder...(18q+19rp)=18(qp)+19(rp)=18(lnblna)+19(lnclna)=18logab+19logacplscheck...
Commented by Tawa1 last updated on 24/Dec/18
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