Question and Answers Forum

All Questions      Topic List

Vector Calculus Questions

Previous in All Question      Next in All Question      

Previous in Vector Calculus      Next in Vector Calculus      

Question Number 5115 by Yozzii last updated on 14/Apr/16

Given the space curve r=r(t), show  that its torsion τ is given by  τ=((r^. •r^(..) ×r^(...) )/(∣r^. ×r^(..) ∣^2 )). It may help to know that its  curvature is numerically given by κ=((∣r^. ×r^(..) ∣)/(∣r^. ∣^3 )).  r^.  is differentiation of r once with  respect to t.

$${Given}\:{the}\:{space}\:{curve}\:\boldsymbol{{r}}=\boldsymbol{{r}}\left({t}\right),\:{show} \\ $$$${that}\:{its}\:{torsion}\:\tau\:{is}\:{given}\:{by} \\ $$$$\tau=\frac{\overset{.} {\boldsymbol{{r}}}\bullet\overset{..} {\boldsymbol{{r}}}×\overset{...} {\boldsymbol{{r}}}}{\mid\overset{.} {\boldsymbol{{r}}}×\overset{..} {\boldsymbol{{r}}}\mid^{\mathrm{2}} }.\:{It}\:{may}\:{help}\:{to}\:{know}\:{that}\:{its} \\ $$$${curvature}\:{is}\:{numerically}\:{given}\:{by}\:\kappa=\frac{\mid\overset{.} {\boldsymbol{{r}}}×\overset{..} {\boldsymbol{{r}}}\mid}{\mid\overset{.} {\boldsymbol{{r}}}\mid^{\mathrm{3}} }. \\ $$$$\overset{.} {\boldsymbol{{r}}}\:{is}\:{differentiation}\:{of}\:\boldsymbol{{r}}\:{once}\:{with} \\ $$$${respect}\:{to}\:{t}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com