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Question Number 51263 by Tawa1 last updated on 25/Dec/18

If  P = 2 + j3 and Q = 2 − j3 and R = j1  Show that  angle  PRQ is right angle

$$\mathrm{If}\:\:\mathrm{P}\:=\:\mathrm{2}\:+\:\mathrm{j3}\:\mathrm{and}\:\mathrm{Q}\:=\:\mathrm{2}\:−\:\mathrm{j3}\:\mathrm{and}\:\mathrm{R}\:=\:\mathrm{j1} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\:\mathrm{angle}\:\:\mathrm{PRQ}\:\mathrm{is}\:\mathrm{right}\:\mathrm{angle} \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 25/Dec/18

P(2,3)   Q(2,−3)   R(0,1)  PQ=6    QR=(√(2^2 +(−4)^2 )) =(√(20))  PR=(√(2^2 +2^2 )) =(√8)   QR^2 +PR^2 ≠PQ^2   pls check question...

$${P}\left(\mathrm{2},\mathrm{3}\right)\:\:\:{Q}\left(\mathrm{2},−\mathrm{3}\right)\:\:\:{R}\left(\mathrm{0},\mathrm{1}\right) \\ $$$${PQ}=\mathrm{6}\:\:\:\:{QR}=\sqrt{\mathrm{2}^{\mathrm{2}} +\left(−\mathrm{4}\right)^{\mathrm{2}} }\:=\sqrt{\mathrm{20}} \\ $$$${PR}=\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} }\:=\sqrt{\mathrm{8}}\: \\ $$$${QR}^{\mathrm{2}} +{PR}^{\mathrm{2}} \neq{PQ}^{\mathrm{2}} \\ $$$${pls}\:{check}\:{question}... \\ $$

Commented by Tawa1 last updated on 25/Dec/18

God bless you sir, i understand

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir},\:\mathrm{i}\:\mathrm{understand} \\ $$

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