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Question Number 51389 by Tawa1 last updated on 26/Dec/18

Commented by tanmay.chaudhury50@gmail.com last updated on 26/Dec/18

$$excellentproblem...givetimetofindtheway$$$$toreachgoal...$$

Commented by Tawa1 last updated on 26/Dec/18

$$\mathrm{Alright}\mathrm{sir},\mathrm{i}\mathrm{will}\mathrm{wait}.\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Answered by Tinkutara last updated on 26/Dec/18

Commented by Tawa1 last updated on 26/Dec/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by Tawa1 last updated on 26/Dec/18

$$\mathrm{But}\mathrm{sir},\mathrm{i}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{really}\mathrm{understand}\mathrm{the}\mathrm{steps}.$$$$\mid \mathrm{a}{\mid }^2={\left(\sqrt{{\mathrm{z}}_1^2+{\mathrm{z}}_2^2+{\mathrm{z}}_3^2}\right)}^2\mathrm{i}\mathrm{think}.\mathrm{please}\mathrm{let}\mathrm{me}\mathrm{understand}$$

Commented by Tawa1 last updated on 27/Dec/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Commented by Tinkutara last updated on 27/Dec/18

$$No,\mid a\mid =a\times \stackrel{-}{a}$$$$Sincez\stackrel{-}{z}=\mid z{\mid }^2$$

Commented by Tawa1 last updated on 28/Dec/18

$$\mathrm{Sir},\mathrm{why}\mathrm{the}\omega \mathrm{interchanged}\mathrm{in}\mid {\mathrm{b}}_1\mid \mathrm{and}\mid {\mathrm{c}}_1\mid ??.$$$${\mathrm{wz}}_2......{\mathrm{w}}^2{\stackrel{-}{\mathrm{z}}}_2.....\mathrm{why}\mathrm{the}\mathrm{change}.$$

Commented by Tawa1 last updated on 27/Dec/18

$$\mathrm{Sir},\mathrm{i}\mathrm{am}\mathrm{trying}\mathrm{to}\mathrm{understand}\mathrm{the}\mathrm{expansion}.$$$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{understand}\mathrm{please}$$

Commented by Tinkutara last updated on 27/Dec/18

I have left some terms there. If you write them, you can see they also add up to 0. What you didn't understand?

Commented by Tinkutara last updated on 28/Dec/18

$$Because\stackrel{-}{\omega }={\omega }^2$$

Commented by Tawa1 last updated on 06/Jan/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by Tawa1 last updated on 06/Jan/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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