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Question Number 5153 by 1771727373 last updated on 23/Apr/16
proofeiΘ=cos(Θ)+isin(Θ)
Answered by 123456 last updated on 23/Apr/16
letsf(θ)=cosθ+isinθ,f(0)=1∂f∂θ=−sinθ+icosθ=i(cosθ+isinθ)=ifdff=idθlnf=iθ+kf=eiθ+k=eiθek=ceiθf(0)=1⇒ce0=c=1f(θ)=eiθ
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