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Question Number 51571 by Tawa1 last updated on 28/Dec/18

If   α − jβ  =  (1/(a − jb))  ,      where   α, β, a, b  are real, express  b  in terms  of  α, β                          Answer:          ((− β)/(α^2  + β^2  − 2α + 1))

Ifαjβ=1ajb,whereα,β,a,barereal,expressbintermsofα,βAnswer:βα2+β22α+1

Answered by tanmay.chaudhury50@gmail.com last updated on 28/Dec/18

a−ib=(1/(α−iβ))  a−ib=((α+iβ)/(α^2 +β^2 ))=((α/(α^2 +β^2 )))+i((β/(α^2 +β^2 )))  b=−((β/(α^2 +β^2 )))  i think so...

aib=1αiβaib=α+iβα2+β2=(αα2+β2)+i(βα2+β2)b=(βα2+β2)ithinkso...

Commented by Tawa1 last updated on 28/Dec/18

God bless you sir.

Godblessyousir.

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