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Question Number 51729 by shivshant0409 last updated on 30/Dec/18

$${81}^{\frac{1}{4}}\times 9^{\frac{3}{2}}\times {27}^{\frac{4}{3}}=\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}$$

Answered by aseerimad last updated on 30/Dec/18

$${81}^{\frac{1}{4}}\times 9^{\frac{3}{2}}\times {27}^{\frac{4}{3}}$$$$={\left(9^2\right)}^{\frac{1}{4}}\times {\left(3^2\right)}^{\frac{3}{2}}\times {\left(3^3\right)}^{\frac{4}{3}}$$$$=9^{\frac{1}{2}}\times \left(3^3\right)\times \left(3^4\right)$$$$=3\times 27\times 81$$$$=6561$$

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