Question and Answers Forum

All Questions      Topic List

Permutation and Combination Questions

Previous in All Question      Next in All Question      

Previous in Permutation and Combination      Next in Permutation and Combination      

Question Number 51779 by aseerimad last updated on 30/Dec/18

Q=  In how many ways 8 students can be divided into two equal groups?    Ans=    ((8!)/(2!×(4!)^2 ))       here why two factorial is divided?  we do not do the same incase of distributing 52 cards equally among 4 persons.    pls explain...

$${Q}=\:\:{In}\:{how}\:{many}\:{ways}\:\mathrm{8}\:{students}\:{can}\:{be}\:{divided}\:{into}\:{two}\:{equal}\:{groups}? \\ $$$$ \\ $$$${Ans}=\:\:\:\:\frac{\mathrm{8}!}{\mathrm{2}!×\left(\mathrm{4}!\right)^{\mathrm{2}} }\:\:\: \\ $$$$ \\ $$$${here}\:{why}\:{two}\:{factorial}\:{is}\:{divided}? \\ $$$${we}\:{do}\:{not}\:{do}\:{the}\:{same}\:{incase}\:{of}\:{distributing}\:\mathrm{52}\:{cards}\:{equally}\:{among}\:\mathrm{4}\:{persons}. \\ $$$$ \\ $$$${pls}\:{explain}... \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 30/Dec/18

Commented by tanmay.chaudhury50@gmail.com last updated on 30/Dec/18

Commented by aseerimad last updated on 30/Dec/18

Thank you

Terms of Service

Privacy Policy

Contact: info@tinkutara.com