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Question Number 51798 by Gulay last updated on 30/Dec/18

Commented by Gulay last updated on 30/Dec/18

$$\mathrm{ENM}=60\mathrm{Find}\mathrm{PEM}$$

Commented by Gulay last updated on 30/Dec/18

$$\mathrm{sir}\mathrm{could}\mathrm{you}\mathrm{help}\mathrm{me}?$$

Commented by tanmay.chaudhury50@gmail.com last updated on 30/Dec/18

$$\mathrm{\angle }PEM=\mathrm{\angle }ENM+\mathrm{\angle }NME$$$$={60}^o+x$$$$nowif△MNEequilateralthenx={60}^o$$$$\mathrm{\angle }PEM={60}^o+{60}^o={120}^o$$

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