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Question Number 52030 by Water last updated on 02/Jan/19
giventhatlog2=0.3010log3=0.477log5=0.699findthevaluesoflog(0.2)
Answered by afachri last updated on 02/Jan/19
log(210)0.5=0.5log(210)=0.5(log2−log10)=0.5(0.3010−1)=−0.3495
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