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Question Number 52200 by gunawan last updated on 04/Jan/19

$$\mathrm{proof}\mathrm{that}$$$$\sqrt{z^2}\ne z,z\in \mathbb{C}$$$$\mathrm{example}$$$$i=\sqrt{-1}$$$$i^2=-1$$$$i^4=1$$$$\sqrt{i^4}\ne i^2$$$$\sqrt{1}\ne -1$$$$1\ne -1$$$$$$

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