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Question Number 52506 by ajfour last updated on 09/Jan/19

Commented by ajfour last updated on 09/Jan/19

$F i n d r a d i i o f b o t h c i r c l e s i n t e r m s$ $o f a a n d b .$
	Answered by mr W last updated on 09/Jan/19

	${(R - a)}^{2} = R (R - b)$ $R^{2} - 2 a R + a^{2} = R^{2} - b R$ $(2 a - b) R = a^{2}$ $\Rightarrow R = \frac{a^{2}}{2 a - b}$ $2 R - 2 r = b$ $\Rightarrow r = R - \frac{b}{2}$ $\Rightarrow r = \frac{a^{2}}{2 a - b} - \frac{b}{2}$
	Commented by ajfour last updated on 09/Jan/19

	$B e s t w a y S i r, t h a n k s a l o t!$
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