Previous in Permutation and Combination Next in Permutation and Combination
Question Number 5275 by sanusihammed last updated on 03/May/16
Answered by Rasheed Soomro last updated on 04/May/16
$$\mathrm{Three}\:\mathrm{members}\:\mathrm{of}\:\mathrm{the}\:\mathrm{commetee}\:\mathrm{of}\:\mathrm{six} \\ $$$$\mathrm{are}\:\mathrm{chairman},\:\mathrm{secratery}\:\mathrm{and}\:\mathrm{treasurer}. \\ $$$$\mathrm{Remaining}\:\mathrm{3}\:\mathrm{members}\:\mathrm{are}\:\mathrm{chosen}\:\mathrm{out}\:\mathrm{of} \\ $$$$\mathrm{7}\:\mathrm{members}: \\ $$$$\:\:\:\:\:\:\:\:\begin{pmatrix}{\mathrm{7}}\\{\mathrm{3}}\end{pmatrix}\:=\frac{\mathrm{7}.\mathrm{6}.\mathrm{5}}{\mathrm{1}.\mathrm{2}.\mathrm{3}}=\mathrm{35}\:\mathrm{ways}. \\ $$